Also, I'm using an old type CW80 (built in 12-05). I have a different model semaphore, so I'm not sure if this reply will be of any use. (It is supposed to appear that the train's starting up was in response to that blade's motion but it is actually the other way around, that the startup changes the signal.)Īfter the train has passed, the bimetallic strip cools down, the contact opens, and the semaphore blade returns to the stop aspect. So, when the contact closes to put voltage on the insulated center rail, it also operates the solenoid, raising the blade and changing the light from red to green. The solenoid inside the 82N is wired between terminals 2 and 4. So, after the delay, the train, which has stopped facing the semaphore, starts up again. Terminal 4 is connected to the insulated center rail. The contact connects 82N terminals 1 and 4 together. When the train approaches the semaphore, the heater begins to heat up and, after an adjustable delay, moves a bimetallic strip to close a contact inside the 82N. Terminal 3 is connected to the outside rails through the contactor (or could be connected to an insulated outside control rail). The lamp is wired between 82N terminals 1 and 2, which are connected to the track outside of the insulated block with 1 connected to the center rail and 2 to the outside rails, so the lamp stays on as long as there is voltage on the track.Ī heater inside the 82N is wired between 82N terminals 1 and 3. Here is my educated guess of how it is supposed to work:
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